Base | Representation |
---|---|
bin | 1010000000010110101010… |
… | …1111100100101110010111 |
3 | 1102221201000200121202001222 |
4 | 2200011222233210232113 |
5 | 2420220430214214033 |
6 | 35221514340440555 |
7 | 2213545020652352 |
oct | 240055257445627 |
9 | 42851020552058 |
10 | 11001202101143 |
11 | 3561646870331 |
12 | 12981343a915b |
13 | 61a5414a29c7 |
14 | 2a0665091299 |
15 | 141276eac598 |
hex | a016abe4b97 |
11001202101143 has 2 divisors, whose sum is σ = 11001202101144. Its totient is φ = 11001202101142.
The previous prime is 11001202101089. The next prime is 11001202101161. The reversal of 11001202101143 is 34110120210011.
11001202101143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11001202101143 - 26 = 11001202101079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11001202107143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500601050571 + 5500601050572.
It is an arithmetic number, because the mean of its divisors is an integer number (5500601050572).
Almost surely, 211001202101143 is an apocalyptic number.
11001202101143 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001202101143 is an equidigital number, since it uses as much as digits as its factorization.
11001202101143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 11001202101143 its reverse (34110120210011), we get a palindrome (45111322311154).
The spelling of 11001202101143 in words is "eleven trillion, one billion, two hundred two million, one hundred one thousand, one hundred forty-three".
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