1100121019973 has 2 divisors, whose sum is σ = 1100121019974. Its totient is φ = 1100121019972.

The previous prime is 1100121019961. The next prime is 1100121020059. The reversal of 1100121019973 is 3799101210011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1072171198849 + 27949821124 = 1035457^2 + 167182^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100121019973 - 2²² = 1100116825669 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100121010973) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550060509986 + 550060509987.

It is an arithmetic number, because the mean of its divisors is an integer number (550060509987).

Almost surely, 2^{1100121019973} is an apocalyptic number.

It is an amenable number.

1100121019973 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100121019973 is an equidigital number, since it uses as much as digits as its factorization.

1100121019973 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3402, while the sum is 35.

Adding to 1100121019973 its reverse (3799101210011), we get a palindrome (4899222229984).

The spelling of 1100121019973 in words is "one trillion, one hundred billion, one hundred twenty-one million, nineteen thousand, nine hundred seventy-three".