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11001211200211 is a prime number
BaseRepresentation
bin1010000000010110101101…
…0010010010001011010011
31102221201001022202000122111
42200011223102102023103
52420220440031401321
635221515303450151
72213545161210301
oct240055322221323
942851038660574
1011001211200211
113561650a15621
121298137456957
1361a54333a47b
142a066637d271
15141277ba85e1
hexa016b4922d3

11001211200211 has 2 divisors, whose sum is σ = 11001211200212. Its totient is φ = 11001211200210.

The previous prime is 11001211200193. The next prime is 11001211200241. The reversal of 11001211200211 is 11200211210011.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11001211200211 - 213 = 11001211192019 is a prime.

It is a super-2 number, since 2×110012112002112 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11001211200191 and 11001211200200.

It is not a weakly prime, because it can be changed into another prime (11001211200241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500605600105 + 5500605600106.

It is an arithmetic number, because the mean of its divisors is an integer number (5500605600106).

Almost surely, 211001211200211 is an apocalyptic number.

11001211200211 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001211200211 is an equidigital number, since it uses as much as digits as its factorization.

11001211200211 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8, while the sum is 13.

Adding to 11001211200211 its reverse (11200211210011), we get a palindrome (22201422410222).

The spelling of 11001211200211 in words is "eleven trillion, one billion, two hundred eleven million, two hundred thousand, two hundred eleven".