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11001211219997 is a prime number
BaseRepresentation
bin1010000000010110101101…
…0010010111000000011101
31102221201001022210000210022
42200011223102113000131
52420220440033014442
635221515304121525
72213545161322055
oct240055322270035
942851038700708
1011001211219997
113561650a29479
1212981374662a5
1361a54334648b
142a0666386565
15141277bae3d2
hexa016b49701d

11001211219997 has 2 divisors, whose sum is σ = 11001211219998. Its totient is φ = 11001211219996.

The previous prime is 11001211219987. The next prime is 11001211220173. The reversal of 11001211219997 is 79991211210011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8756071592356 + 2245139627641 = 2959066^2 + 1498379^2 .

It is a cyclic number.

It is not a de Polignac number, because 11001211219997 - 218 = 11001210957853 is a prime.

It is a super-2 number, since 2×110012112199972 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11001211219987) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500605609998 + 5500605609999.

It is an arithmetic number, because the mean of its divisors is an integer number (5500605609999).

Almost surely, 211001211219997 is an apocalyptic number.

It is an amenable number.

11001211219997 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001211219997 is an equidigital number, since it uses as much as digits as its factorization.

11001211219997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20412, while the sum is 44.

The spelling of 11001211219997 in words is "eleven trillion, one billion, two hundred eleven million, two hundred nineteen thousand, nine hundred ninety-seven".