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110012112212122 = 255006056106061
BaseRepresentation
bin11001000000111000110000…
…110111101001000010011010
3112102112001111020210220120001
4121000320300313221002122
5103404414301211241442
61025550511110323214
732113053460600411
oct3100706067510232
9472461436726501
10110012112212122
113206496937445a
121040910195950a
134950136764193
141d2488680c478
15caba02c4b2b7
hex640e30de909a

110012112212122 has 4 divisors (see below), whose sum is σ = 165018168318186. Its totient is φ = 55006056106060.

The previous prime is 110012112212059. The next prime is 110012112212147. The reversal of 110012112212122 is 221212211210011.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 98407808645041 + 11604303567081 = 9920071^2 + 3406509^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 110012112212122.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27503028053029 + ... + 27503028053032.

Almost surely, 2110012112212122 is an apocalyptic number.

110012112212122 is a deficient number, since it is larger than the sum of its proper divisors (55006056106064).

110012112212122 is an equidigital number, since it uses as much as digits as its factorization.

110012112212122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 55006056106063.

The product of its (nonzero) digits is 64, while the sum is 19.

Adding to 110012112212122 its reverse (221212211210011), we get a palindrome (331224323422133).

The spelling of 110012112212122 in words is "one hundred ten trillion, twelve billion, one hundred twelve million, two hundred twelve thousand, one hundred twenty-two".

Divisors: 1 2 55006056106061 110012112212122