Base | Representation |
---|---|
bin | 1010000000010110101101… |
… | …1001111101111011111111 |
3 | 1102221201001110112100200102 |
4 | 2200011223121331323333 |
5 | 2420220441040330323 |
6 | 35221515414551315 |
7 | 2213545214266613 |
oct | 240055331757377 |
9 | 42851043470612 |
10 | 11001213214463 |
11 | 356165207099a |
12 | 129813806853b |
13 | 61a543894234 |
14 | 2a0666745343 |
15 | 141277e55328 |
hex | a016b67deff |
11001213214463 has 2 divisors, whose sum is σ = 11001213214464. Its totient is φ = 11001213214462.
The previous prime is 11001213214429. The next prime is 11001213214477. The reversal of 11001213214463 is 36441231210011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11001213214463 - 228 = 11000944779007 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11001213214163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500606607231 + 5500606607232.
It is an arithmetic number, because the mean of its divisors is an integer number (5500606607232).
Almost surely, 211001213214463 is an apocalyptic number.
11001213214463 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001213214463 is an equidigital number, since it uses as much as digits as its factorization.
11001213214463 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 29.
Adding to 11001213214463 its reverse (36441231210011), we get a palindrome (47442444424474).
The spelling of 11001213214463 in words is "eleven trillion, one billion, two hundred thirteen million, two hundred fourteen thousand, four hundred sixty-three".
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