| Base | Representation |
|---|---|
| bin | 1010000000010110101101… |
| … | …1010011000011101011100 |
| 3 | 1102221201001110201212201000 |
| 4 | 2200011223122120131130 |
| 5 | 2420220441102314400 |
| 6 | 35221515421150300 |
| 7 | 2213545215231420 |
| oct | 240055332303534 |
| 9 | 42851043655630 |
| 10 | 11001213323100 |
| 11 | 3561652135580 |
| 12 | 12981380bb390 |
| 13 | 61a543901810 |
| 14 | 2a0666772b80 |
| 15 | 141277e77600 |
| hex | a016b69875c |
11001213323100 has 1152 divisors, whose sum is σ = 48382163343360. Its totient is φ = 2070282240000.
The previous prime is 11001213323053. The next prime is 11001213323101. The reversal of 11001213323100 is 132331210011.
11001213323100 is a `hidden beast` number, since 1 + 1 + 0 + 0 + 1 + 21 + 332 + 310 + 0 = 666.
It is a super-2 number, since 2×110012133231002 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11001213323101) by changing a digit.
It is a polite number, since it can be written in 383 ways as a sum of consecutive naturals, for example, 143204700 + ... + 143281500.
It is an arithmetic number, because the mean of its divisors is an integer number (41998405680).
Almost surely, 211001213323100 is an apocalyptic number.
11001213323100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 11001213323100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (24191081671680).
11001213323100 is an abundant number, since it is smaller than the sum of its proper divisors (37380950020260).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11001213323100 is a wasteful number, since it uses less digits than its factorization.
11001213323100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 76908 (or 76895 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 18.
Adding to 11001213323100 its reverse (132331210011), we get a palindrome (11133544533111).
The spelling of 11001213323100 in words is "eleven trillion, one billion, two hundred thirteen million, three hundred twenty-three thousand, one hundred".
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