110012210020133 has 2 divisors, whose sum is σ = 110012210020134. Its totient is φ = 110012210020132.

The previous prime is 110012210020123. The next prime is 110012210020267. The reversal of 110012210020133 is 331020012210011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 74986195534849 + 35026014485284 = 8659457^2 + 5918278^2 .

It is a cyclic number.

It is not a de Polignac number, because 110012210020133 - 2¹⁰ = 110012210019109 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110012210020123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55006105010066 + 55006105010067.

It is an arithmetic number, because the mean of its divisors is an integer number (55006105010067).

Almost surely, 2^{110012210020133} is an apocalyptic number.

It is an amenable number.

110012210020133 is a deficient number, since it is larger than the sum of its proper divisors (1).

110012210020133 is an equidigital number, since it uses as much as digits as its factorization.

110012210020133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 110012210020133 its reverse (331020012210011), we get a palindrome (441032222230144).

The spelling of 110012210020133 in words is "one hundred ten trillion, twelve billion, two hundred ten million, twenty thousand, one hundred thirty-three".