Base | Representation |
---|---|
bin | 110011001110101001… |
… | …0010101010011010001 |
3 | 101111221222220000022122 |
4 | 1212131102111103101 |
5 | 3300301312324103 |
6 | 122312252344025 |
7 | 10643140110563 |
oct | 1463522252321 |
9 | 344858800278 |
10 | 110013011153 |
11 | 42724527631 |
12 | 193a3175015 |
13 | a4b3104206 |
14 | 5478c0d333 |
15 | 2cdd317b38 |
hex | 199d4954d1 |
110013011153 has 2 divisors, whose sum is σ = 110013011154. Its totient is φ = 110013011152.
The previous prime is 110013011137. The next prime is 110013011159. The reversal of 110013011153 is 351110310011.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 82778770369 + 27234240784 = 287713^2 + 165028^2 .
It is a cyclic number.
It is not a de Polignac number, because 110013011153 - 24 = 110013011137 is a prime.
It is not a weakly prime, because it can be changed into another prime (110013011159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55006505576 + 55006505577.
It is an arithmetic number, because the mean of its divisors is an integer number (55006505577).
Almost surely, 2110013011153 is an apocalyptic number.
It is an amenable number.
110013011153 is a deficient number, since it is larger than the sum of its proper divisors (1).
110013011153 is an equidigital number, since it uses as much as digits as its factorization.
110013011153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 45, while the sum is 17.
Adding to 110013011153 its reverse (351110310011), we get a palindrome (461123321164).
The spelling of 110013011153 in words is "one hundred ten billion, thirteen million, eleven thousand, one hundred fifty-three".
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