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1100130331310 = 25110013033131
BaseRepresentation
bin10000000000100100111…
…000001010101010101110
310220011121222022021200022
4100000210320022222232
5121011031331100220
62201220511002142
7142324153345133
oct20004470125256
93804558267608
101100130331310
1139462098991a
12159267509352
137c984aab7aa
143b36491258a
151d93c147925
hex10024e0aaae

1100130331310 has 8 divisors (see below), whose sum is σ = 1980234596376. Its totient is φ = 440052132520.

The previous prime is 1100130331241. The next prime is 1100130331357. The reversal of 1100130331310 is 131330310011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×11001303313102 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55006516556 + ... + 55006516575.

It is an arithmetic number, because the mean of its divisors is an integer number (247529324547).

Almost surely, 21100130331310 is an apocalyptic number.

1100130331310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1100130331310 is a deficient number, since it is larger than the sum of its proper divisors (880104265066).

1100130331310 is a wasteful number, since it uses less digits than its factorization.

1100130331310 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 110013033138.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 1100130331310 its reverse (131330310011), we get a palindrome (1231460641321).

The spelling of 1100130331310 in words is "one trillion, one hundred billion, one hundred thirty million, three hundred thirty-one thousand, three hundred ten".

Divisors: 1 2 5 10 110013033131 220026066262 550065165655 1100130331310