Base | Representation |
---|---|
bin | 10100011111011101… |
… | …01001001110101111 |
3 | 1001101200220010222002 |
4 | 22033232221032233 |
5 | 140012313211413 |
6 | 5015352042515 |
7 | 536423353355 |
oct | 121756511657 |
9 | 31350803862 |
10 | 11001303983 |
11 | 4735a4956a |
12 | 217039343b |
13 | 1064293037 |
14 | 76512d7d5 |
15 | 445c4a958 |
hex | 28fba93af |
11001303983 has 2 divisors, whose sum is σ = 11001303984. Its totient is φ = 11001303982.
The previous prime is 11001303979. The next prime is 11001304009. The reversal of 11001303983 is 38930310011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11001303983 - 22 = 11001303979 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11001309983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500651991 + 5500651992.
It is an arithmetic number, because the mean of its divisors is an integer number (5500651992).
Almost surely, 211001303983 is an apocalyptic number.
11001303983 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001303983 is an equidigital number, since it uses as much as digits as its factorization.
11001303983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 29.
Adding to 11001303983 its reverse (38930310011), we get a palindrome (49931613994).
The spelling of 11001303983 in words is "eleven billion, one million, three hundred three thousand, nine hundred eighty-three".
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