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110013114103 is a prime number
BaseRepresentation
bin110011001110101001…
…0101110011011110111
3101111222000002020112121
41212131102232123313
53300301324122403
6122312254500411
710643141016664
oct1463522563367
9344860066477
10110013114103
1142724597a12
12193a3204707
13a4b313c029
145478c38a6b
152cdd3383bd
hex199d4ae6f7

110013114103 has 2 divisors, whose sum is σ = 110013114104. Its totient is φ = 110013114102.

The previous prime is 110013114073. The next prime is 110013114109. The reversal of 110013114103 is 301411310011.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-110013114103 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110013114109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55006557051 + 55006557052.

It is an arithmetic number, because the mean of its divisors is an integer number (55006557052).

Almost surely, 2110013114103 is an apocalyptic number.

110013114103 is a deficient number, since it is larger than the sum of its proper divisors (1).

110013114103 is an equidigital number, since it uses as much as digits as its factorization.

110013114103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 16.

Adding to 110013114103 its reverse (301411310011), we get a palindrome (411424424114).

The spelling of 110013114103 in words is "one hundred ten billion, thirteen million, one hundred fourteen thousand, one hundred three".