Base | Representation |
---|---|
bin | 10000000000100100111… |
… | …110111010101001111101 |
3 | 10220011122002122011212111 |
4 | 100000210332322221331 |
5 | 121011032304210413 |
6 | 2201221012534021 |
7 | 142324204364611 |
oct | 20004476725175 |
9 | 3804562564774 |
10 | 1100132100733 |
11 | 394621988256 |
12 | 159268021311 |
13 | 7c98527aca3 |
14 | 3b364c53341 |
15 | 1d93c396d3d |
hex | 10024fbaa7d |
1100132100733 has 2 divisors, whose sum is σ = 1100132100734. Its totient is φ = 1100132100732.
The previous prime is 1100132100721. The next prime is 1100132100799. The reversal of 1100132100733 is 3370012310011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 687304005444 + 412828095289 = 829038^2 + 642517^2 .
It is an emirp because it is prime and its reverse (3370012310011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1100132100733 - 217 = 1100131969661 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100132100713) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550066050366 + 550066050367.
It is an arithmetic number, because the mean of its divisors is an integer number (550066050367).
Almost surely, 21100132100733 is an apocalyptic number.
It is an amenable number.
1100132100733 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100132100733 is an equidigital number, since it uses as much as digits as its factorization.
1100132100733 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 378, while the sum is 22.
Adding to 1100132100733 its reverse (3370012310011), we get a palindrome (4470144410744).
The spelling of 1100132100733 in words is "one trillion, one hundred billion, one hundred thirty-two million, one hundred thousand, seven hundred thirty-three".
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