Base | Representation |
---|---|
bin | 10000000000100101000… |
… | …011100100110100101111 |
3 | 10220011122011221020011202 |
4 | 100000211003210310233 |
5 | 121011033112301111 |
6 | 2201221055040115 |
7 | 142324220642342 |
oct | 20004503446457 |
9 | 3804564836152 |
10 | 1100133322031 |
11 | 394622641897 |
12 | 15926851003b |
13 | 7c9855b7b53 |
14 | 3b365090459 |
15 | 1d93c538b3b |
hex | 100250e4d2f |
1100133322031 has 2 divisors, whose sum is σ = 1100133322032. Its totient is φ = 1100133322030.
The previous prime is 1100133321961. The next prime is 1100133322037. The reversal of 1100133322031 is 1302233310011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1100133322031 - 214 = 1100133305647 is a prime.
It is a super-2 number, since 2×11001333220312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1100133321994 and 1100133322012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100133322037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550066661015 + 550066661016.
It is an arithmetic number, because the mean of its divisors is an integer number (550066661016).
Almost surely, 21100133322031 is an apocalyptic number.
1100133322031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100133322031 is an equidigital number, since it uses as much as digits as its factorization.
1100133322031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 1100133322031 its reverse (1302233310011), we get a palindrome (2402366632042).
The spelling of 1100133322031 in words is "one trillion, one hundred billion, one hundred thirty-three million, three hundred twenty-two thousand, thirty-one".
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