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110013431412 = 22311637882877
BaseRepresentation
bin110011001110101001…
…1111011111001110100
3101111222000200100210210
41212131103323321310
53300301414301122
6122312305345420
710643143511043
oct1463523737164
9344860610723
10110013431412
1142724794355
12193a3338270
13a4b32205a1
145478cbc55a
152cdd39c40c
hex199d4fbe74

110013431412 has 24 divisors (see below), whose sum is σ = 256918759776. Its totient is φ = 36639607648.

The previous prime is 110013431351. The next prime is 110013431443. The reversal of 110013431412 is 214134310011.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3927483 + ... + 3955394.

It is an arithmetic number, because the mean of its divisors is an integer number (10704948324).

Almost surely, 2110013431412 is an apocalyptic number.

110013431412 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

110013431412 is an abundant number, since it is smaller than the sum of its proper divisors (146905328364).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

110013431412 is a wasteful number, since it uses less digits than its factorization.

110013431412 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7884047 (or 7884045 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 110013431412 its reverse (214134310011), we get a palindrome (324147741423).

The spelling of 110013431412 in words is "one hundred ten billion, thirteen million, four hundred thirty-one thousand, four hundred twelve".

Divisors: 1 2 3 4 6 12 1163 2326 3489 4652 6978 13956 7882877 15765754 23648631 31531508 47297262 94594524 9167785951 18335571902 27503357853 36671143804 55006715706 110013431412