1100140134311 has 2 divisors, whose sum is σ = 1100140134312. Its totient is φ = 1100140134310.

The previous prime is 1100140134287. The next prime is 1100140134391. The reversal of 1100140134311 is 1134310410011.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1100140134311 is a prime.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100140134391) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550070067155 + 550070067156.

It is an arithmetic number, because the mean of its divisors is an integer number (550070067156).

Almost surely, 2^{1100140134311} is an apocalyptic number.

1100140134311 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100140134311 is an equidigital number, since it uses as much as digits as its factorization.

1100140134311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 1100140134311 its reverse (1134310410011), we get a palindrome (2234450544322).

The spelling of 1100140134311 in words is "one trillion, one hundred billion, one hundred forty million, one hundred thirty-four thousand, three hundred eleven".