110014040041 has 2 divisors, whose sum is σ = 110014040042. Its totient is φ = 110014040040.

The previous prime is 110014039997. The next prime is 110014040089. The reversal of 110014040041 is 140040410011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 93884024025 + 16130016016 = 306405^2 + 127004^2 .

It is a cyclic number.

It is not a de Polignac number, because 110014040041 - 2²³ = 110005651433 is a prime.

It is a super-2 number, since 2×110014040041² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 110014039997 and 110014040024.

It is not a weakly prime, because it can be changed into another prime (110014640041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55007020020 + 55007020021.

It is an arithmetic number, because the mean of its divisors is an integer number (55007020021).

Almost surely, 2^110014040041 is an apocalyptic number.

It is an amenable number.

110014040041 is a deficient number, since it is larger than the sum of its proper divisors (1).

110014040041 is an equidigital number, since it uses as much as digits as its factorization.

110014040041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64, while the sum is 16.

Adding to 110014040041 its reverse (140040410011), we get a palindrome (250054450052).

The spelling of 110014040041 in words is "one hundred ten billion, fourteen million, forty thousand, forty-one".