Base | Representation |
---|---|
bin | 10000000000100101100… |
… | …101000110111001001111 |
3 | 10220011122210110211012120 |
4 | 100000211211012321033 |
5 | 121011042340043320 |
6 | 2201222011304023 |
7 | 142324355443140 |
oct | 20004545067117 |
9 | 3804583424176 |
10 | 1100142112335 |
11 | 3946275a6102 |
12 | 15926b44b013 |
13 | 7c987374c06 |
14 | 3b3662dbac7 |
15 | 1d93d1c3440 |
hex | 10025946e4f |
1100142112335 has 64 divisors (see below), whose sum is σ = 2063816229888. Its totient is φ = 490056182784.
The previous prime is 1100142112313. The next prime is 1100142112337. The reversal of 1100142112335 is 5332112410011.
It is not a de Polignac number, because 1100142112335 - 218 = 1100141850191 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1100142112337) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 228432 + ... + 1500821.
It is an arithmetic number, because the mean of its divisors is an integer number (32247128592).
Almost surely, 21100142112335 is an apocalyptic number.
1100142112335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1100142112335 is a deficient number, since it is larger than the sum of its proper divisors (963674117553).
1100142112335 is a wasteful number, since it uses less digits than its factorization.
1100142112335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1729424.
The product of its (nonzero) digits is 720, while the sum is 24.
Adding to 1100142112335 its reverse (5332112410011), we get a palindrome (6432254522346).
The spelling of 1100142112335 in words is "one trillion, one hundred billion, one hundred forty-two million, one hundred twelve thousand, three hundred thirty-five".
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