Base | Representation |
---|---|
bin | 10100011111011110… |
… | …00101110110111001 |
3 | 1001101201010002210222 |
4 | 22033233011312321 |
5 | 140012330434431 |
6 | 5015354345425 |
7 | 536424352256 |
oct | 121757056671 |
9 | 31351102728 |
10 | 11001421241 |
11 | 4736019678 |
12 | 217042b275 |
13 | 1064304515 |
14 | 76516042d |
15 | 445c7057b |
hex | 28fbc5db9 |
11001421241 has 2 divisors, whose sum is σ = 11001421242. Its totient is φ = 11001421240.
The previous prime is 11001421231. The next prime is 11001421357. The reversal of 11001421241 is 14212410011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10877655616 + 123765625 = 104296^2 + 11125^2 .
It is an emirp because it is prime and its reverse (14212410011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11001421241 - 214 = 11001404857 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (11001421201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500710620 + 5500710621.
It is an arithmetic number, because the mean of its divisors is an integer number (5500710621).
Almost surely, 211001421241 is an apocalyptic number.
It is an amenable number.
11001421241 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001421241 is an equidigital number, since it uses as much as digits as its factorization.
11001421241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 11001421241 its reverse (14212410011), we get a palindrome (25213831252).
The spelling of 11001421241 in words is "eleven billion, one million, four hundred twenty-one thousand, two hundred forty-one".
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