Base | Representation |
---|---|
bin | 10100011111011110… |
… | …01000110001111101 |
3 | 1001101201010201020101 |
4 | 22033233020301331 |
5 | 140012331330323 |
6 | 5015354521101 |
7 | 536424432211 |
oct | 121757106175 |
9 | 31351121211 |
10 | 11001433213 |
11 | 4736027671 |
12 | 2170436191 |
13 | 1064309ac4 |
14 | 765164941 |
15 | 445c73dad |
hex | 28fbc8c7d |
11001433213 has 2 divisors, whose sum is σ = 11001433214. Its totient is φ = 11001433212.
The previous prime is 11001433151. The next prime is 11001433253. The reversal of 11001433213 is 31233410011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5675060889 + 5326372324 = 75333^2 + 72982^2 .
It is an emirp because it is prime and its reverse (31233410011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11001433213 - 217 = 11001302141 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11001433253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500716606 + 5500716607.
It is an arithmetic number, because the mean of its divisors is an integer number (5500716607).
Almost surely, 211001433213 is an apocalyptic number.
It is an amenable number.
11001433213 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001433213 is an equidigital number, since it uses as much as digits as its factorization.
11001433213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 11001433213 its reverse (31233410011), we get a palindrome (42234843224).
The spelling of 11001433213 in words is "eleven billion, one million, four hundred thirty-three thousand, two hundred thirteen".
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