Base | Representation |
---|---|
bin | 1010000000010111100010… |
… | …1100101010101001110001 |
3 | 1102221201122000011012210101 |
4 | 2200011320230222221301 |
5 | 2420221420133020032 |
6 | 35221553502432401 |
7 | 2213553562641565 |
oct | 240057054525161 |
9 | 42851560135711 |
10 | 11001436220017 |
11 | 3561756a37301 |
12 | 129819a892701 |
13 | 61a57ab44999 |
14 | 2a06881d56a5 |
15 | 14128c805de7 |
hex | a0178b2aa71 |
11001436220017 has 2 divisors, whose sum is σ = 11001436220018. Its totient is φ = 11001436220016.
The previous prime is 11001436219981. The next prime is 11001436220143. The reversal of 11001436220017 is 71002263410011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10878063872481 + 123372347536 = 3298191^2 + 351244^2 .
It is a cyclic number.
It is not a de Polignac number, because 11001436220017 - 219 = 11001435695729 is a prime.
It is not a weakly prime, because it can be changed into another prime (11001436220317) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500718110008 + 5500718110009.
It is an arithmetic number, because the mean of its divisors is an integer number (5500718110009).
Almost surely, 211001436220017 is an apocalyptic number.
It is an amenable number.
11001436220017 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001436220017 is an equidigital number, since it uses as much as digits as its factorization.
11001436220017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 28.
Adding to 11001436220017 its reverse (71002263410011), we get a palindrome (82003699630028).
The spelling of 11001436220017 in words is "eleven trillion, one billion, four hundred thirty-six million, two hundred twenty thousand, seventeen".
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