11001436220143 has 2 divisors, whose sum is σ = 11001436220144. Its totient is φ = 11001436220142.

The previous prime is 11001436220017. The next prime is 11001436220171. The reversal of 11001436220143 is 34102263410011.

11001436220143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an a-pointer prime, because the next prime (11001436220171) can be obtained adding 11001436220143 to its sum of digits (28).

It is a strong prime.

It is an emirp because it is prime and its reverse (34102263410011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11001436220143 - 2¹³ = 11001436211951 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11001436220543) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500718110071 + 5500718110072.

It is an arithmetic number, because the mean of its divisors is an integer number (5500718110072).

Almost surely, 2^{11001436220143} is an apocalyptic number.

11001436220143 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001436220143 is an equidigital number, since it uses as much as digits as its factorization.

11001436220143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 11001436220143 its reverse (34102263410011), we get a palindrome (45103699630154).

The spelling of 11001436220143 in words is "eleven trillion, one billion, four hundred thirty-six million, two hundred twenty thousand, one hundred forty-three".