11001983 has 2 divisors, whose sum is σ = 11001984. Its totient is φ = 11001982.

The previous prime is 11001973. The next prime is 11002001. The reversal of 11001983 is 38910011.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11001983 - 2⁴ = 11001967 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11001923) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500991 + 5500992.

It is an arithmetic number, because the mean of its divisors is an integer number (5500992).

Almost surely, 2^11001983 is an apocalyptic number.

11001983 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001983 is an equidigital number, since it uses as much as digits as its factorization.

11001983 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 23.

The square root of 11001983 is about 3316.9237253817. The cubic root of 11001983 is about 222.4113723525.

Adding to 11001983 its reverse (38910011), we get a palindrome (49911994).

The spelling of 11001983 in words is "eleven million, one thousand, nine hundred eighty-three".