11002000033 has 2 divisors, whose sum is σ = 11002000034. Its totient is φ = 11002000032.

The previous prime is 11002000013. The next prime is 11002000049. The reversal of 11002000033 is 33000020011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6572831329 + 4429168704 = 81073^2 + 66552^2 .

It is a cyclic number.

It is not a de Polignac number, because 11002000033 - 2⁵ = 11002000001 is a prime.

It is a super-2 number, since 2×11002000033² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11001999983 and 11002000019.

It is not a weakly prime, because it can be changed into another prime (11002000013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501000016 + 5501000017.

It is an arithmetic number, because the mean of its divisors is an integer number (5501000017).

Almost surely, 2^11002000033 is an apocalyptic number.

It is an amenable number.

11002000033 is a deficient number, since it is larger than the sum of its proper divisors (1).

11002000033 is an equidigital number, since it uses as much as digits as its factorization.

11002000033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 10.

Adding to 11002000033 its reverse (33000020011), we get a palindrome (44002020044).

The spelling of 11002000033 in words is "eleven billion, two million, thirty-three", and thus it is an aban number and an uban number.