Base | Representation |
---|---|
bin | 10000000000101001000… |
… | …001111110000100010011 |
3 | 10220011210211102022212122 |
4 | 100000221001332010103 |
5 | 121011202200310003 |
6 | 2201231440244455 |
7 | 142325660533043 |
oct | 20005101760423 |
9 | 3804724368778 |
10 | 1100200010003 |
11 | 394657250516 |
12 | 15928691072b |
13 | 7c996366ca3 |
14 | 3b36dc8d723 |
15 | 1d94330d238 |
hex | 1002907e113 |
1100200010003 has 2 divisors, whose sum is σ = 1100200010004. Its totient is φ = 1100200010002.
The previous prime is 1100200009967. The next prime is 1100200010011. The reversal of 1100200010003 is 3000100020011.
It is an a-pointer prime, because the next prime (1100200010011) can be obtained adding 1100200010003 to its sum of digits (8).
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1100200010003 is a prime.
It is not a weakly prime, because it can be changed into another prime (1100200010083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550100005001 + 550100005002.
It is an arithmetic number, because the mean of its divisors is an integer number (550100005002).
Almost surely, 21100200010003 is an apocalyptic number.
1100200010003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100200010003 is an equidigital number, since it uses as much as digits as its factorization.
1100200010003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6, while the sum is 8.
Adding to 1100200010003 its reverse (3000100020011), we get a palindrome (4100300030014).
The spelling of 1100200010003 in words is "one trillion, one hundred billion, two hundred million, ten thousand, three".
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