11002000903 has 2 divisors, whose sum is σ = 11002000904. Its totient is φ = 11002000902.

The previous prime is 11002000873. The next prime is 11002000927. The reversal of 11002000903 is 30900020011.

11002000903 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11002000903 - 2⁵ = 11002000871 is a prime.

It is a super-2 number, since 2×11002000903² (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11009000903) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501000451 + 5501000452.

It is an arithmetic number, because the mean of its divisors is an integer number (5501000452).

Almost surely, 2^11002000903 is an apocalyptic number.

11002000903 is a deficient number, since it is larger than the sum of its proper divisors (1).

11002000903 is an equidigital number, since it uses as much as digits as its factorization.

11002000903 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 11002000903 its reverse (30900020011), we get a palindrome (41902020914).

The spelling of 11002000903 in words is "eleven billion, two million, nine hundred three", and thus it is an aban number.