Base | Representation |
---|---|
bin | 1010000000011001101001… |
… | …1111101011100110110111 |
3 | 1102221210002112002212220022 |
4 | 2200012122133223212313 |
5 | 2420224100312211044 |
6 | 35222130035555355 |
7 | 2213603616355262 |
oct | 240063237534667 |
9 | 42853075085808 |
10 | 11002003241399 |
11 | 3561a1800a915 |
12 | 129831875bb5b |
13 | 61a63b4648b1 |
14 | 2a06dd635cd9 |
15 | 1412c24ac3ee |
hex | a019a7eb9b7 |
11002003241399 has 2 divisors, whose sum is σ = 11002003241400. Its totient is φ = 11002003241398.
The previous prime is 11002003241347. The next prime is 11002003241479. The reversal of 11002003241399 is 99314230020011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11002003241399 - 220 = 11002002192823 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11002003241699) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501001620699 + 5501001620700.
It is an arithmetic number, because the mean of its divisors is an integer number (5501001620700).
Almost surely, 211002003241399 is an apocalyptic number.
11002003241399 is a deficient number, since it is larger than the sum of its proper divisors (1).
11002003241399 is an equidigital number, since it uses as much as digits as its factorization.
11002003241399 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11664, while the sum is 35.
The spelling of 11002003241399 in words is "eleven trillion, two billion, three million, two hundred forty-one thousand, three hundred ninety-nine".
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