Base | Representation |
---|---|
bin | 10000000000101001000… |
… | …110100000100110000011 |
3 | 10220011210220122210020201 |
4 | 100000221012200212003 |
5 | 121011203001400003 |
6 | 2201231521550031 |
7 | 142326003620323 |
oct | 20005106404603 |
9 | 3804726583221 |
10 | 1100201200003 |
11 | 394657993594 |
12 | 1592871a5317 |
13 | 7c996692829 |
14 | 3b3700bd283 |
15 | 1d943495b1d |
hex | 100291a0983 |
1100201200003 has 2 divisors, whose sum is σ = 1100201200004. Its totient is φ = 1100201200002.
The previous prime is 1100201199991. The next prime is 1100201200031. The reversal of 1100201200003 is 3000021020011.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1100201200003 is a prime.
It is not a weakly prime, because it can be changed into another prime (1100201200073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550100600001 + 550100600002.
It is an arithmetic number, because the mean of its divisors is an integer number (550100600002).
Almost surely, 21100201200003 is an apocalyptic number.
1100201200003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100201200003 is an equidigital number, since it uses as much as digits as its factorization.
1100201200003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 10.
Adding to 1100201200003 its reverse (3000021020011), we get a palindrome (4100222220014).
The spelling of 1100201200003 in words is "one trillion, one hundred billion, two hundred one million, two hundred thousand, three".
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