Base | Representation |
---|---|
bin | 1010000000011001101101… |
… | …1111100100011101100111 |
3 | 1102221210010200121202202211 |
4 | 2200012123133210131213 |
5 | 2420224114104124401 |
6 | 35222131434544251 |
7 | 2213604211621156 |
oct | 240063337443547 |
9 | 42853120552684 |
10 | 11002019989351 |
11 | 3561a265098a6 |
12 | 1298322298087 |
13 | 61a641a79a21 |
14 | 2a070195559d |
15 | 1412c3bb9951 |
hex | a019b7e4767 |
11002019989351 has 2 divisors, whose sum is σ = 11002019989352. Its totient is φ = 11002019989350.
The previous prime is 11002019989333. The next prime is 11002019989423. The reversal of 11002019989351 is 15398991020011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11002019989351 - 215 = 11002019956583 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11002019989295 and 11002019989304.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11002019989451) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501009994675 + 5501009994676.
It is an arithmetic number, because the mean of its divisors is an integer number (5501009994676).
Almost surely, 211002019989351 is an apocalyptic number.
11002019989351 is a deficient number, since it is larger than the sum of its proper divisors (1).
11002019989351 is an equidigital number, since it uses as much as digits as its factorization.
11002019989351 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 174960, while the sum is 49.
The spelling of 11002019989351 in words is "eleven trillion, two billion, nineteen million, nine hundred eighty-nine thousand, three hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •