Base | Representation |
---|---|
bin | 1010000000011001101101… |
… | …1111101011111010000011 |
3 | 1102221210010200200022121011 |
4 | 2200012123133223322003 |
5 | 2420224114111113333 |
6 | 35222131435341351 |
7 | 2213604212106106 |
oct | 240063337537203 |
9 | 42853120608534 |
10 | 11002020019843 |
11 | 3561a2652a7a6 |
12 | 12983222b1857 |
13 | 61a641a8a878 |
14 | 2a070196273d |
15 | 1412c3bc39cd |
hex | a019b7ebe83 |
11002020019843 has 2 divisors, whose sum is σ = 11002020019844. Its totient is φ = 11002020019842.
The previous prime is 11002020019841. The next prime is 11002020019853. The reversal of 11002020019843 is 34891002020011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11002020019843 - 21 = 11002020019841 is a prime.
It is a super-2 number, since 2×110020200198432 (a number of 27 digits) contains 22 as substring.
Together with 11002020019841, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (11002020019841) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501010009921 + 5501010009922.
It is an arithmetic number, because the mean of its divisors is an integer number (5501010009922).
Almost surely, 211002020019843 is an apocalyptic number.
11002020019843 is a deficient number, since it is larger than the sum of its proper divisors (1).
11002020019843 is an equidigital number, since it uses as much as digits as its factorization.
11002020019843 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 31.
Adding to 11002020019843 its reverse (34891002020011), we get a palindrome (45893022039854).
The spelling of 11002020019843 in words is "eleven trillion, two billion, twenty million, nineteen thousand, eight hundred forty-three".
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