110020212001121 has 2 divisors, whose sum is σ = 110020212001122. Its totient is φ = 110020212001120.

The previous prime is 110020212001111. The next prime is 110020212001123. The reversal of 110020212001121 is 121100212020011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 107486321088721 + 2533890912400 = 10367561^2 + 1591820^2 .

It is a cyclic number.

It is not a de Polignac number, because 110020212001121 - 2¹⁴ = 110020211984737 is a prime.

Together with 110020212001123, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 110020212001096 and 110020212001105.

It is not a weakly prime, because it can be changed into another prime (110020212001123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55010106000560 + 55010106000561.

It is an arithmetic number, because the mean of its divisors is an integer number (55010106000561).

Almost surely, 2^{110020212001121} is an apocalyptic number.

It is an amenable number.

110020212001121 is a deficient number, since it is larger than the sum of its proper divisors (1).

110020212001121 is an equidigital number, since it uses as much as digits as its factorization.

110020212001121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16, while the sum is 14.

Adding to 110020212001121 its reverse (121100212020011), we get a palindrome (231120424021132).

The spelling of 110020212001121 in words is "one hundred ten trillion, twenty billion, two hundred twelve million, one thousand, one hundred twenty-one".