Base | Representation |
---|---|
bin | 10100011111100010… |
… | …11101111110001111 |
3 | 1001101202021202111100 |
4 | 22033301131332033 |
5 | 140013010404203 |
6 | 5015415554143 |
7 | 536432555625 |
oct | 121761357617 |
9 | 31352252440 |
10 | 11002044303 |
11 | 47364047a8 |
12 | 217068b953 |
13 | 1064491cb3 |
14 | 765283515 |
15 | 445d44ea3 |
hex | 28fc5df8f |
11002044303 has 24 divisors (see below), whose sum is σ = 16236350208. Its totient is φ = 7175815632.
The previous prime is 11002044299. The next prime is 11002044311. The reversal of 11002044303 is 30344020011.
It is not a de Polignac number, because 11002044303 - 22 = 11002044299 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11002044103) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1995076 + ... + 2000582.
It is an arithmetic number, because the mean of its divisors is an integer number (676514592).
Almost surely, 211002044303 is an apocalyptic number.
11002044303 is a deficient number, since it is larger than the sum of its proper divisors (5234305905).
11002044303 is a wasteful number, since it uses less digits than its factorization.
11002044303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10283 (or 10280 counting only the distinct ones).
The product of its (nonzero) digits is 288, while the sum is 18.
Adding to 11002044303 its reverse (30344020011), we get a palindrome (41346064314).
The spelling of 11002044303 in words is "eleven billion, two million, forty-four thousand, three hundred three".
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