Search a number
-
+
1100207925697 is a prime number
BaseRepresentation
bin10000000000101001100…
…000001010100111000001
310220011211101022111011111
4100000221200022213001
5121011211212110242
62201232322043321
7142326115031626
oct20005140124701
93804741274144
101100207925697
11394660767711
121592894a9541
137c997ba8c2a
143b370d5034d
151d943d73817
hex1002980a9c1

1100207925697 has 2 divisors, whose sum is σ = 1100207925698. Its totient is φ = 1100207925696.

The previous prime is 1100207925689. The next prime is 1100207925701. The reversal of 1100207925697 is 7965297020011.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1082413432881 + 17794492816 = 1040391^2 + 133396^2 .

It is an emirp because it is prime and its reverse (7965297020011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1100207925697 - 23 = 1100207925689 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1100207925697.

It is not a weakly prime, because it can be changed into another prime (1100207923697) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550103962848 + 550103962849.

It is an arithmetic number, because the mean of its divisors is an integer number (550103962849).

Almost surely, 21100207925697 is an apocalyptic number.

It is an amenable number.

1100207925697 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100207925697 is an equidigital number, since it uses as much as digits as its factorization.

1100207925697 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 476280, while the sum is 49.

The spelling of 1100207925697 in words is "one trillion, one hundred billion, two hundred seven million, nine hundred twenty-five thousand, six hundred ninety-seven".