11002100112343 has 2 divisors, whose sum is σ = 11002100112344. Its totient is φ = 11002100112342.

The previous prime is 11002100112307. The next prime is 11002100112431. The reversal of 11002100112343 is 34321100120011.

It is a weak prime.

It is an emirp because it is prime and its reverse (34321100120011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11002100112343 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11002100112343.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11002100112743) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501050056171 + 5501050056172.

It is an arithmetic number, because the mean of its divisors is an integer number (5501050056172).

Almost surely, 2^{11002100112343} is an apocalyptic number.

11002100112343 is a deficient number, since it is larger than the sum of its proper divisors (1).

11002100112343 is an equidigital number, since it uses as much as digits as its factorization.

11002100112343 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 11002100112343 its reverse (34321100120011), we get a palindrome (45323200232354).

The spelling of 11002100112343 in words is "eleven trillion, two billion, one hundred million, one hundred twelve thousand, three hundred forty-three".