Base | Representation |
---|---|
bin | 11001000001000001000100… |
… | …100101110000100010111101 |
3 | 112102112220111221212001100111 |
4 | 121001001010211300202331 |
5 | 103410041033422100242 |
6 | 1025554544222030021 |
7 | 32113520522221561 |
oct | 3101010445604275 |
9 | 472486457761314 |
10 | 110021033003197 |
11 | 32068726984868 |
12 | 1040a991418311 |
13 | 4950c289a0194 |
14 | 1d250914c56a1 |
15 | cabd75ecd817 |
hex | 6410449708bd |
110021033003197 has 2 divisors, whose sum is σ = 110021033003198. Its totient is φ = 110021033003196.
The previous prime is 110021033003111. The next prime is 110021033003213. The reversal of 110021033003197 is 791300330120011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 93415685102041 + 16605347901156 = 9665179^2 + 4074966^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110021033003197 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110021033043197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55010516501598 + 55010516501599.
It is an arithmetic number, because the mean of its divisors is an integer number (55010516501599).
Almost surely, 2110021033003197 is an apocalyptic number.
It is an amenable number.
110021033003197 is a deficient number, since it is larger than the sum of its proper divisors (1).
110021033003197 is an equidigital number, since it uses as much as digits as its factorization.
110021033003197 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3402, while the sum is 31.
The spelling of 110021033003197 in words is "one hundred ten trillion, twenty-one billion, thirty-three million, three thousand, one hundred ninety-seven".
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