Base | Representation |
---|---|
bin | 11001000001000001001000… |
… | …101001100111000111011011 |
3 | 112102112220200201000211210112 |
4 | 121001001020221213013123 |
5 | 103410041203341401021 |
6 | 1025554555054034535 |
7 | 32113522310221652 |
oct | 3101011051470733 |
9 | 472486621024715 |
10 | 110021101122011 |
11 | 32068761380502 |
12 | 1040a9b01a8a4b |
13 | 4950c39b30681 |
14 | 1d2509a578199 |
15 | cabd7be86d5b |
hex | 641048a671db |
110021101122011 has 2 divisors, whose sum is σ = 110021101122012. Its totient is φ = 110021101122010.
The previous prime is 110021101121891. The next prime is 110021101122013. The reversal of 110021101122011 is 110221101120011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110021101122011 - 214 = 110021101105627 is a prime.
It is a Sophie Germain prime.
Together with 110021101122013, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (110021101122013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55010550561005 + 55010550561006.
It is an arithmetic number, because the mean of its divisors is an integer number (55010550561006).
Almost surely, 2110021101122011 is an apocalyptic number.
110021101122011 is a deficient number, since it is larger than the sum of its proper divisors (1).
110021101122011 is an equidigital number, since it uses as much as digits as its factorization.
110021101122011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 14.
Adding to 110021101122011 its reverse (110221101120011), we get a palindrome (220242202242022).
The spelling of 110021101122011 in words is "one hundred ten trillion, twenty-one billion, one hundred one million, one hundred twenty-two thousand, eleven".
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