110021120113 has 2 divisors, whose sum is σ = 110021120114. Its totient is φ = 110021120112.

The previous prime is 110021120093. The next prime is 110021120161. The reversal of 110021120113 is 311021120011.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 90497485584 + 19523634529 = 300828^2 + 139727^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-110021120113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110021120093 and 110021120102.

It is not a weakly prime, because it can be changed into another prime (110021120173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55010560056 + 55010560057.

It is an arithmetic number, because the mean of its divisors is an integer number (55010560057).

Almost surely, 2^110021120113 is an apocalyptic number.

It is an amenable number.

110021120113 is a deficient number, since it is larger than the sum of its proper divisors (1).

110021120113 is an equidigital number, since it uses as much as digits as its factorization.

110021120113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 110021120113 its reverse (311021120011), we get a palindrome (421042240124).

The spelling of 110021120113 in words is "one hundred ten billion, twenty-one million, one hundred twenty thousand, one hundred thirteen".