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110021216377153 is a prime number
BaseRepresentation
bin11001000001000001001111…
…100001010001100101000001
3112102112220222201220102010111
4121001001033201101211001
5103410041422343032103
61025555014332231321
732113525206661534
oct3101011741214501
9472486881812114
10110021216377153
1132068810441394
121040aa2290b541
134950c57985993
141d250ab9baa1b
15cabd8715186d
hex64104f851941

110021216377153 has 2 divisors, whose sum is σ = 110021216377154. Its totient is φ = 110021216377152.

The previous prime is 110021216377087. The next prime is 110021216377243. The reversal of 110021216377153 is 351773612120011.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 107869972286209 + 2151244090944 = 10386047^2 + 1466712^2 .

It is a cyclic number.

It is not a de Polignac number, because 110021216377153 - 213 = 110021216368961 is a prime.

It is not a weakly prime, because it can be changed into another prime (110021216372153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55010608188576 + 55010608188577.

It is an arithmetic number, because the mean of its divisors is an integer number (55010608188577).

Almost surely, 2110021216377153 is an apocalyptic number.

It is an amenable number.

110021216377153 is a deficient number, since it is larger than the sum of its proper divisors (1).

110021216377153 is an equidigital number, since it uses as much as digits as its factorization.

110021216377153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 52920, while the sum is 40.

Adding to 110021216377153 its reverse (351773612120011), we get a palindrome (461794828497164).

The spelling of 110021216377153 in words is "one hundred ten trillion, twenty-one billion, two hundred sixteen million, three hundred seventy-seven thousand, one hundred fifty-three".