110021220014051 has 2 divisors, whose sum is σ = 110021220014052. Its totient is φ = 110021220014050.

The previous prime is 110021220014003. The next prime is 110021220014053. The reversal of 110021220014051 is 150410022120011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 110021220014051 - 2⁴² = 105623173502947 is a prime.

Together with 110021220014053, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (110021220014053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55010610007025 + 55010610007026.

It is an arithmetic number, because the mean of its divisors is an integer number (55010610007026).

Almost surely, 2^{110021220014051} is an apocalyptic number.

110021220014051 is a deficient number, since it is larger than the sum of its proper divisors (1).

110021220014051 is an equidigital number, since it uses as much as digits as its factorization.

110021220014051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 160, while the sum is 20.

Adding to 110021220014051 its reverse (150410022120011), we get a palindrome (260431242134062).

The spelling of 110021220014051 in words is "one hundred ten trillion, twenty-one billion, two hundred twenty million, fourteen thousand, fifty-one".