Base | Representation |
---|---|
bin | 110011001110111000… |
… | …1101001101100011111 |
3 | 101111222120100010022122 |
4 | 1212131301221230133 |
5 | 3300310413034101 |
6 | 122313144333155 |
7 | 10643266643462 |
oct | 1463561515437 |
9 | 344876303278 |
10 | 110021221151 |
11 | 42729124956 |
12 | 193a5a741bb |
13 | a4b4a1a0ba |
14 | 5479d492d9 |
15 | 2cdddda51b |
hex | 199dc69b1f |
110021221151 has 2 divisors, whose sum is σ = 110021221152. Its totient is φ = 110021221150.
The previous prime is 110021221139. The next prime is 110021221169. The reversal of 110021221151 is 151122120011.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110021221151 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110021241151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55010610575 + 55010610576.
It is an arithmetic number, because the mean of its divisors is an integer number (55010610576).
Almost surely, 2110021221151 is an apocalyptic number.
110021221151 is a deficient number, since it is larger than the sum of its proper divisors (1).
110021221151 is an equidigital number, since it uses as much as digits as its factorization.
110021221151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40, while the sum is 17.
Adding to 110021221151 its reverse (151122120011), we get a palindrome (261143341162).
The spelling of 110021221151 in words is "one hundred ten billion, twenty-one million, two hundred twenty-one thousand, one hundred fifty-one".
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