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11002122220130 = 251100212222013
BaseRepresentation
bin1010000000011010000110…
…0101100011001001100010
31102221210101210222122000222
42200012201211203021202
52420224321242021010
635222145530043042
72213606562564116
oct240064145431142
942853353878028
1011002122220130
113561a79194348
121298350579482
1361a659cc1a02
142a0711367746
151412ccb60355
hexa01a1963262

11002122220130 has 8 divisors (see below), whose sum is σ = 19803819996252. Its totient is φ = 4400848888048.

The previous prime is 11002122220079. The next prime is 11002122220147. The reversal of 11002122220130 is 3102222120011.

It can be written as a sum of positive squares in 2 ways, for example, as 9732833823001 + 1269288397129 = 3119749^2 + 1126627^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 11002122220099 and 11002122220108.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 550106110997 + ... + 550106111016.

Almost surely, 211002122220130 is an apocalyptic number.

11002122220130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11002122220130 is a deficient number, since it is larger than the sum of its proper divisors (8801697776122).

11002122220130 is a wasteful number, since it uses less digits than its factorization.

11002122220130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1100212222020.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 11002122220130 its reverse (3102222120011), we get a palindrome (14104344340141).

The spelling of 11002122220130 in words is "eleven trillion, two billion, one hundred twenty-two million, two hundred twenty thousand, one hundred thirty".

Divisors: 1 2 5 10 1100212222013 2200424444026 5501061110065 11002122220130