Base | Representation |
---|---|
bin | 10000000000101001110… |
… | …000101100100001000011 |
3 | 10220011211200110122011212 |
4 | 100000221300230201003 |
5 | 121011213314241013 |
6 | 2201232555000335 |
7 | 142326166620053 |
oct | 20005160544103 |
9 | 3804750418155 |
10 | 1100212258883 |
11 | 394663157261 |
12 | 15928aa390ab |
13 | 7c998a6534a |
14 | 3b37175b563 |
15 | 1d94442c6a8 |
hex | 10029c2c843 |
1100212258883 has 2 divisors, whose sum is σ = 1100212258884. Its totient is φ = 1100212258882.
The previous prime is 1100212258799. The next prime is 1100212258889. The reversal of 1100212258883 is 3888522120011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1100212258883 - 226 = 1100145150019 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1100212258883.
It is not a weakly prime, because it can be changed into another prime (1100212258889) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550106129441 + 550106129442.
It is an arithmetic number, because the mean of its divisors is an integer number (550106129442).
Almost surely, 21100212258883 is an apocalyptic number.
1100212258883 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100212258883 is an equidigital number, since it uses as much as digits as its factorization.
1100212258883 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 61440, while the sum is 41.
Adding to 1100212258883 its reverse (3888522120011), we get a palindrome (4988734378894).
The spelling of 1100212258883 in words is "one trillion, one hundred billion, two hundred twelve million, two hundred fifty-eight thousand, eight hundred eighty-three".
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