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1100212258889 is a prime number
BaseRepresentation
bin10000000000101001110…
…000101100100001001001
310220011211200110122012002
4100000221300230201021
5121011213314241024
62201232555000345
7142326166620062
oct20005160544111
93804750418162
101100212258889
11394663157267
1215928aa390b5
137c998a65353
143b37175b569
151d94442c6ae
hex10029c2c849

1100212258889 has 2 divisors, whose sum is σ = 1100212258890. Its totient is φ = 1100212258888.

The previous prime is 1100212258883. The next prime is 1100212258891. The reversal of 1100212258889 is 9888522120011.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1072657918864 + 27554340025 = 1035692^2 + 165995^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1100212258889 is a prime.

Together with 1100212258891, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1100212258883) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550106129444 + 550106129445.

It is an arithmetic number, because the mean of its divisors is an integer number (550106129445).

Almost surely, 21100212258889 is an apocalyptic number.

It is an amenable number.

1100212258889 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100212258889 is an equidigital number, since it uses as much as digits as its factorization.

1100212258889 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 184320, while the sum is 47.

The spelling of 1100212258889 in words is "one trillion, one hundred billion, two hundred twelve million, two hundred fifty-eight thousand, eight hundred eighty-nine".