1100212999789 has 2 divisors, whose sum is σ = 1100212999790. Its totient is φ = 1100212999788.

The previous prime is 1100212999777. The next prime is 1100212999843. The reversal of 1100212999789 is 9879992120011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 953274944164 + 146938055625 = 976358^2 + 383325^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100212999789 - 2⁵ = 1100212999757 is a prime.

It is a super-2 number, since 2×1100212999789² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100212999709) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550106499894 + 550106499895.

It is an arithmetic number, because the mean of its divisors is an integer number (550106499895).

Almost surely, 2^{1100212999789} is an apocalyptic number.

It is an amenable number.

1100212999789 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100212999789 is an equidigital number, since it uses as much as digits as its factorization.

1100212999789 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1469664, while the sum is 58.

The spelling of 1100212999789 in words is "one trillion, one hundred billion, two hundred twelve million, nine hundred ninety-nine thousand, seven hundred eighty-nine".