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1100213000437 is a prime number
BaseRepresentation
bin10000000000101001110…
…011100001100011110101
310220011211201212022101211
4100000221303201203311
5121011214012003222
62201233022521421
7142326206126035
oct20005163414365
93804751768354
101100213000437
11394663613411
1215928b136271
137c998c64a35
143b3718b18c5
151d944527277
hex10029ce18f5

1100213000437 has 2 divisors, whose sum is σ = 1100213000438. Its totient is φ = 1100213000436.

The previous prime is 1100213000303. The next prime is 1100213000443. The reversal of 1100213000437 is 7340003120011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 803328593796 + 296884406641 = 896286^2 + 544871^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100213000437 - 211 = 1100212998389 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100213000137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550106500218 + 550106500219.

It is an arithmetic number, because the mean of its divisors is an integer number (550106500219).

Almost surely, 21100213000437 is an apocalyptic number.

It is an amenable number.

1100213000437 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100213000437 is an equidigital number, since it uses as much as digits as its factorization.

1100213000437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504, while the sum is 22.

Adding to 1100213000437 its reverse (7340003120011), we get a palindrome (8440216120448).

The spelling of 1100213000437 in words is "one trillion, one hundred billion, two hundred thirteen million, four hundred thirty-seven", and thus it is an aban number.