1100213030051 has 2 divisors, whose sum is σ = 1100213030052. Its totient is φ = 1100213030050.

The previous prime is 1100213030047. The next prime is 1100213030053. The reversal of 1100213030051 is 1500303120011.

It is a strong prime.

It is an emirp because it is prime and its reverse (1500303120011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1100213030051 - 2² = 1100213030047 is a prime.

It is a super-2 number, since 2×1100213030051² (a number of 25 digits) contains 22 as substring.

Together with 1100213030053, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1100213030053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550106515025 + 550106515026.

It is an arithmetic number, because the mean of its divisors is an integer number (550106515026).

Almost surely, 2^{1100213030051} is an apocalyptic number.

1100213030051 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100213030051 is an equidigital number, since it uses as much as digits as its factorization.

1100213030051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 90, while the sum is 17.

Adding to 1100213030051 its reverse (1500303120011), we get a palindrome (2600516150062).

The spelling of 1100213030051 in words is "one trillion, one hundred billion, two hundred thirteen million, thirty thousand, fifty-one".