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1100213201120 = 2551141891631051
BaseRepresentation
bin10000000000101001110…
…100010010100011100000
310220011211202020111200112
4100000221310102203200
5121011214034413440
62201233031110452
7142326210623105
oct20005164224340
93804752214615
101100213201120
11394663740170
1215928b212428
137c999005197
143b371924aac
151d944566965
hex10029d128e0

1100213201120 has 384 divisors, whose sum is σ = 2958178890240. Its totient is φ = 383201280000.

The previous prime is 1100213201093. The next prime is 1100213201123. The reversal of 1100213201120 is 211023120011.

It is a junction number, because it is equal to n+sod(n) for n = 1100213201095 and 1100213201104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1100213201123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1046824595 + ... + 1046825645.

It is an arithmetic number, because the mean of its divisors is an integer number (7703590860).

Almost surely, 21100213201120 is an apocalyptic number.

1100213201120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1100213201120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1479089445120).

1100213201120 is an abundant number, since it is smaller than the sum of its proper divisors (1857965689120).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1100213201120 is a wasteful number, since it uses less digits than its factorization.

1100213201120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1370 (or 1362 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 1100213201120 its reverse (211023120011), we get a palindrome (1311236321131).

The spelling of 1100213201120 in words is "one trillion, one hundred billion, two hundred thirteen million, two hundred one thousand, one hundred twenty".