Base | Representation |
---|---|
bin | 10100011111100011… |
… | …10110011010011101 |
3 | 1001101202110211211010 |
4 | 22033301312122131 |
5 | 140013022110123 |
6 | 5015422045433 |
7 | 536433453531 |
oct | 121761663235 |
9 | 31352424733 |
10 | 11002144413 |
11 | 4736472a37 |
12 | 2170719879 |
13 | 10644c8730 |
14 | 7652abbc1 |
15 | 445d64993 |
hex | 28fc7669d |
11002144413 has 32 divisors (see below), whose sum is σ = 16152256512. Its totient is φ = 6619032000.
The previous prime is 11002144409. The next prime is 11002144457. The reversal of 11002144413 is 31444120011.
It is not a de Polignac number, because 11002144413 - 22 = 11002144409 is a prime.
It is a super-2 number, since 2×110021444132 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11002144413.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11002144463) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1923628 + ... + 1929338.
It is an arithmetic number, because the mean of its divisors is an integer number (504758016).
Almost surely, 211002144413 is an apocalyptic number.
11002144413 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
11002144413 is a deficient number, since it is larger than the sum of its proper divisors (5150112099).
11002144413 is a wasteful number, since it uses less digits than its factorization.
11002144413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6825.
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 11002144413 its reverse (31444120011), we get a palindrome (42446264424).
The spelling of 11002144413 in words is "eleven billion, two million, one hundred forty-four thousand, four hundred thirteen".
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