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1100220102133 is a prime number
BaseRepresentation
bin10000000000101010001…
…110100111010111110101
310220011212020020010002121
4100000222032213113311
5121011222321232013
62201233435035541
7142326323364505
oct20005216472765
93804766203077
101100220102133
11394667623a89
1215929159bbb1
137c99a580319
143b3727dda05
151d944e7b58d
hex1002a3a75f5

1100220102133 has 2 divisors, whose sum is σ = 1100220102134. Its totient is φ = 1100220102132.

The previous prime is 1100220102101. The next prime is 1100220102143. The reversal of 1100220102133 is 3312010220011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 694225572804 + 405994529329 = 833202^2 + 637177^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100220102133 - 25 = 1100220102101 is a prime.

It is a super-2 number, since 2×11002201021332 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100220102143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550110051066 + 550110051067.

It is an arithmetic number, because the mean of its divisors is an integer number (550110051067).

Almost surely, 21100220102133 is an apocalyptic number.

It is an amenable number.

1100220102133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100220102133 is an equidigital number, since it uses as much as digits as its factorization.

1100220102133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 1100220102133 its reverse (3312010220011), we get a palindrome (4412230322144).

The spelling of 1100220102133 in words is "one trillion, one hundred billion, two hundred twenty million, one hundred two thousand, one hundred thirty-three".