Base | Representation |
---|---|
bin | 10000000000101010001… |
… | …110111111110000100110 |
3 | 10220011212020102012010012 |
4 | 100000222032333300212 |
5 | 121011222332431042 |
6 | 2201233441130222 |
7 | 142326324261644 |
oct | 20005216776046 |
9 | 3804766365105 |
10 | 1100220202022 |
11 | 394667692037 |
12 | 159291629972 |
13 | 7c99a5b6926 |
14 | 3b372828194 |
15 | 1d944e9ae82 |
hex | 1002a3bfc26 |
1100220202022 has 4 divisors (see below), whose sum is σ = 1650330303036. Its totient is φ = 550110101010.
The previous prime is 1100220201943. The next prime is 1100220202033. The reversal of 1100220202022 is 2202020220011.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 1100220201988 and 1100220202006.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275055050504 + ... + 275055050507.
It is an arithmetic number, because the mean of its divisors is an integer number (412582575759).
Almost surely, 21100220202022 is an apocalyptic number.
1100220202022 is a deficient number, since it is larger than the sum of its proper divisors (550110101014).
1100220202022 is an equidigital number, since it uses as much as digits as its factorization.
1100220202022 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 550110101013.
The product of its (nonzero) digits is 64, while the sum is 14.
Adding to 1100220202022 its reverse (2202020220011), we get a palindrome (3302240422033).
The spelling of 1100220202022 in words is "one trillion, one hundred billion, two hundred twenty million, two hundred two thousand, twenty-two".
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